Merge pull request 'develop' (#1) from develop into main

Reviewed-on: #1
Reviewed-by: Hosein Asfiaee
This commit was merged in pull request #1.
This commit is contained in:
2026-07-30 13:09:23 +00:00
3 changed files with 188 additions and 16 deletions
Generated
+1
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@@ -0,0 +1 @@
MainExercises.java
+110 -6
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@@ -20,7 +20,7 @@ public class BonusExercises {
- Each segment (between dots) must follow same hyphen rules
*/
public boolean validateEmail(String email) {
String regex = ""; // todo
String regex = "^[a-zA-Z0-9_+-]+(?:\\.[a-zA-Z0-9_+-]+)*@(?:[a-zA-Z0-9-]+\\.)+[a-zA-Z0-9-]+$";
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(email);
@@ -38,11 +38,31 @@ public class BonusExercises {
If no match for a date is found in the string, return null.
*/
public String findDate(String string) {
// todo
public String findDate(String text) {
if (text == null || text.isBlank()) {
return null;
}
String dateRegex =
"\\b(?:"
+ "\\d{4}[-/](?:0[1-9]|1[0-2])[-/](?:0[1-9]|[12]\\d|3[01])"
+ "|"
+ "(?:0[1-9]|[12]\\d|3[01])/(?:0[1-9]|1[0-2])/\\d{4}"
+ "|"
+ "(?:0[1-9]|1[0-2])/(?:0[1-9]|[12]\\d|3[01])/\\d{4}"
+ ")\\b";
Matcher matcher = Pattern.compile(dateRegex).matcher(text);
if (matcher.find()) {
return matcher.group();
}
return null;
}
/*
given a string, implement the method to detect all valid passwords
then, it should return the count of them
@@ -54,8 +74,60 @@ public class BonusExercises {
- has no white-space in it
*/
public int findValidPasswords(String string) {
// todo
return -1;
int count = 0;
for (int i = 0; i <= string.length() - 8;) {
int bestJ = -1;
for (int j = i + 8; j <= string.length(); j++) {
String tempPassword = string.substring(i,j);
if (tempPassword.contains(" ")){
continue;
}
boolean hasSpecialCharacter = false;
boolean hasDigit = false;
boolean hasLowercase = false;
boolean hasUppercase = false;
String specialChars = "!@#$%^&*";
String digits = "1234567890";
String lowerCases = "abcdefghijklmnopqrstuvwxyz";
String upperCases = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
for (int k = 0; k < tempPassword.length(); k++) {
char currentChar = tempPassword.charAt(k);
if (specialChars.contains(String.valueOf(currentChar))){
hasSpecialCharacter = true;
} else if (upperCases.contains(String.valueOf(currentChar))) {
hasUppercase = true;
} else if (lowerCases.contains(String.valueOf(currentChar))) {
hasLowercase = true;
} else if (digits.contains(String.valueOf(currentChar))) {
hasDigit = true;
}
}
if (hasDigit && hasLowercase && hasUppercase && hasSpecialCharacter){
count++;
i = j;
bestJ = j;
break;
}
}
if (bestJ == -1){
i++;
}
}
return count;
}
/*
@@ -64,9 +136,41 @@ public class BonusExercises {
note: your implementation should be case-insensitive, e.g. Aba -> is palindrome
*/
public boolean isPalindrome(String word) {
if (word.length() == 1){
return false;
}
String lowerWord = word.toLowerCase();
StringBuilder mutableInverse = new StringBuilder(lowerWord.length());
for (int i = lowerWord.length() - 1; i >= 0; i--){
mutableInverse.append(lowerWord.charAt(i));
}
String inverseOfWord = mutableInverse.toString();
return lowerWord.equals(inverseOfWord);
}
public List<String> findPalindromes(String string) {
List<String> list = new ArrayList<>();
// todo
String[] wordsArray = string.split("\\s+");
for (String s : wordsArray){
String finalS = s;
if (finalS.endsWith(",")) {
finalS = finalS.substring(0, finalS.length() - 1);
}
if (finalS.isEmpty()) {
continue;
}
if (isPalindrome(finalS)){
list.add(finalS);
}
}
return list;
}
+77 -10
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@@ -1,3 +1,5 @@
import java.util.ArrayList;
public class MainExercises
{
/*
@@ -19,10 +21,18 @@ public class MainExercises
the output has to be a two-dimensional array of characters, so don't just print the triangle!
*/
public char[][] generateTriangle(int n) {
char[][] triangle = new char[n][];
for(int i = 0; i < n; i++) {
triangle[i] = new char[i+1];
for(int j = 0; j <= i; j++){
if(j == 0 || i == n - 1 || i == j)
triangle[i][j] = '*';
else
triangle[i][j] = ' ';
}
}
// todo
return null;
return triangle;
}
@@ -58,10 +68,38 @@ public class MainExercises
- Number of columns: matrix[0].length (if rectangular)
*/
public int[] spiralTraversal(int[][] matrix) {
// todo
return null;
int rows = matrix.length;
int cols = matrix[0].length;
int[] result = new int[rows * cols];
int index = 0;
int top = 0, bottom = rows - 1;
int left = 0, right = cols - 1;
while (top <= bottom && left <= right) {
for (int j = left; j <= right; j++) {
result[index++] = matrix[top][j];
}
top++;
for (int i = top; i <= bottom; i++) {
result[index++] = matrix[i][right];
}
right--;
if (top <= bottom) {
for (int j = right; j >= left; j--) {
result[index++] = matrix[bottom][j];
}
bottom--;
}
if (left <= right) {
for (int i = bottom; i >= top; i--) {
result[index++] = matrix[i][left];
}
left++;
}
}
return result;
}
/*
integer partitioning is a combinatorics problem in discreet maths
the problem is to generate sum numbers which their summation is the input number
@@ -89,15 +127,44 @@ public class MainExercises
If you're familiar with Lists and ArrayLists, you can also edit the method's
body to use them instead of arrays.
*/
private ArrayList<ArrayList<Integer>> intPartitionsHelper(int n, int biggest) {
ArrayList<ArrayList<Integer>> result = new ArrayList<>();
if (n == 0) {
result.add(new ArrayList<>());
return result;
}
for (int k = 1; k <= Math.min(biggest, n); k++) {
ArrayList<ArrayList<Integer>> subPartitions = intPartitionsHelper(n - k, k);
for (ArrayList<Integer> subPartition : subPartitions) {
ArrayList<Integer> newPartition = new ArrayList<>();
newPartition.add(k);
newPartition.addAll(subPartition);
result.add(newPartition);
}
}
return result;
}
public int[][] intPartitions(int n) {
// todo
return null;
ArrayList<ArrayList<Integer>> answerList = intPartitionsHelper(n, n);
int[][] answerArray = new int[answerList.size()][];
for(int i = 0; i < answerList.size(); i++){
answerArray[(answerList.size() - i) - 1] = new int[answerList.get(i).size()];
for(int j = 0; j < answerList.get(i).size(); j++){
answerArray[(answerList.size() - i) - 1][j] = answerList.get(i).get(j);
}
}
return answerArray;
}
public static void main()
public void main()
{
int n = 4;
int[][] partitions = intPartitions(n);
for (int i = 0; i < partitions.length; i++) {
for(int j = 0; j < partitions[i].length; j++)
System.out.print(partitions[i][j]);
System.out.println();
}
}
}