Merge pull request 'develop' (#1) from develop into main
Reviewed-on: #1 Reviewed-by: Hosein Asfiaee
This commit was merged in pull request #1.
This commit is contained in:
Generated
+1
@@ -0,0 +1 @@
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MainExercises.java
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@@ -20,7 +20,7 @@ public class BonusExercises {
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- Each segment (between dots) must follow same hyphen rules
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*/
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public boolean validateEmail(String email) {
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String regex = ""; // todo
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String regex = "^[a-zA-Z0-9_+-]+(?:\\.[a-zA-Z0-9_+-]+)*@(?:[a-zA-Z0-9-]+\\.)+[a-zA-Z0-9-]+$";
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Pattern pattern = Pattern.compile(regex);
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Matcher matcher = pattern.matcher(email);
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@@ -38,11 +38,31 @@ public class BonusExercises {
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If no match for a date is found in the string, return null.
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*/
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public String findDate(String string) {
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// todo
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public String findDate(String text) {
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if (text == null || text.isBlank()) {
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return null;
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}
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String dateRegex =
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"\\b(?:"
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+ "\\d{4}[-/](?:0[1-9]|1[0-2])[-/](?:0[1-9]|[12]\\d|3[01])"
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+ "|"
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+ "(?:0[1-9]|[12]\\d|3[01])/(?:0[1-9]|1[0-2])/\\d{4}"
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+ "|"
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+ "(?:0[1-9]|1[0-2])/(?:0[1-9]|[12]\\d|3[01])/\\d{4}"
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+ ")\\b";
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Matcher matcher = Pattern.compile(dateRegex).matcher(text);
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if (matcher.find()) {
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return matcher.group();
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}
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return null;
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}
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/*
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given a string, implement the method to detect all valid passwords
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then, it should return the count of them
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@@ -54,8 +74,60 @@ public class BonusExercises {
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- has no white-space in it
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*/
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public int findValidPasswords(String string) {
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// todo
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return -1;
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int count = 0;
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for (int i = 0; i <= string.length() - 8;) {
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int bestJ = -1;
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for (int j = i + 8; j <= string.length(); j++) {
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String tempPassword = string.substring(i,j);
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if (tempPassword.contains(" ")){
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continue;
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}
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boolean hasSpecialCharacter = false;
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boolean hasDigit = false;
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boolean hasLowercase = false;
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boolean hasUppercase = false;
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String specialChars = "!@#$%^&*";
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String digits = "1234567890";
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String lowerCases = "abcdefghijklmnopqrstuvwxyz";
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String upperCases = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
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for (int k = 0; k < tempPassword.length(); k++) {
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char currentChar = tempPassword.charAt(k);
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if (specialChars.contains(String.valueOf(currentChar))){
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hasSpecialCharacter = true;
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} else if (upperCases.contains(String.valueOf(currentChar))) {
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hasUppercase = true;
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} else if (lowerCases.contains(String.valueOf(currentChar))) {
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hasLowercase = true;
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} else if (digits.contains(String.valueOf(currentChar))) {
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hasDigit = true;
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}
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}
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if (hasDigit && hasLowercase && hasUppercase && hasSpecialCharacter){
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count++;
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i = j;
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bestJ = j;
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break;
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}
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}
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if (bestJ == -1){
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i++;
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}
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}
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return count;
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}
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/*
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@@ -64,9 +136,41 @@ public class BonusExercises {
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note: your implementation should be case-insensitive, e.g. Aba -> is palindrome
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*/
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public boolean isPalindrome(String word) {
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if (word.length() == 1){
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return false;
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}
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String lowerWord = word.toLowerCase();
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StringBuilder mutableInverse = new StringBuilder(lowerWord.length());
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for (int i = lowerWord.length() - 1; i >= 0; i--){
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mutableInverse.append(lowerWord.charAt(i));
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}
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String inverseOfWord = mutableInverse.toString();
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return lowerWord.equals(inverseOfWord);
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}
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public List<String> findPalindromes(String string) {
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List<String> list = new ArrayList<>();
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// todo
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String[] wordsArray = string.split("\\s+");
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for (String s : wordsArray){
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String finalS = s;
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if (finalS.endsWith(",")) {
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finalS = finalS.substring(0, finalS.length() - 1);
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}
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if (finalS.isEmpty()) {
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continue;
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}
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if (isPalindrome(finalS)){
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list.add(finalS);
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}
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}
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return list;
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}
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@@ -1,3 +1,5 @@
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import java.util.ArrayList;
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public class MainExercises
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{
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/*
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@@ -19,10 +21,18 @@ public class MainExercises
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the output has to be a two-dimensional array of characters, so don't just print the triangle!
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*/
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public char[][] generateTriangle(int n) {
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char[][] triangle = new char[n][];
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for(int i = 0; i < n; i++) {
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triangle[i] = new char[i+1];
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for(int j = 0; j <= i; j++){
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if(j == 0 || i == n - 1 || i == j)
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triangle[i][j] = '*';
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else
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triangle[i][j] = ' ';
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}
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}
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// todo
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return null;
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return triangle;
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}
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@@ -58,10 +68,38 @@ public class MainExercises
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- Number of columns: matrix[0].length (if rectangular)
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*/
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public int[] spiralTraversal(int[][] matrix) {
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// todo
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return null;
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int rows = matrix.length;
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int cols = matrix[0].length;
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int[] result = new int[rows * cols];
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int index = 0;
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int top = 0, bottom = rows - 1;
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int left = 0, right = cols - 1;
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while (top <= bottom && left <= right) {
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for (int j = left; j <= right; j++) {
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result[index++] = matrix[top][j];
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}
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top++;
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for (int i = top; i <= bottom; i++) {
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result[index++] = matrix[i][right];
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}
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right--;
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if (top <= bottom) {
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for (int j = right; j >= left; j--) {
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result[index++] = matrix[bottom][j];
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}
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bottom--;
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}
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if (left <= right) {
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for (int i = bottom; i >= top; i--) {
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result[index++] = matrix[i][left];
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}
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left++;
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}
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}
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return result;
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}
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/*
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integer partitioning is a combinatorics problem in discreet maths
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the problem is to generate sum numbers which their summation is the input number
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@@ -89,15 +127,44 @@ public class MainExercises
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If you're familiar with Lists and ArrayLists, you can also edit the method's
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body to use them instead of arrays.
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*/
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private ArrayList<ArrayList<Integer>> intPartitionsHelper(int n, int biggest) {
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ArrayList<ArrayList<Integer>> result = new ArrayList<>();
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if (n == 0) {
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result.add(new ArrayList<>());
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return result;
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}
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for (int k = 1; k <= Math.min(biggest, n); k++) {
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ArrayList<ArrayList<Integer>> subPartitions = intPartitionsHelper(n - k, k);
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for (ArrayList<Integer> subPartition : subPartitions) {
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ArrayList<Integer> newPartition = new ArrayList<>();
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newPartition.add(k);
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newPartition.addAll(subPartition);
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result.add(newPartition);
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}
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}
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return result;
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}
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public int[][] intPartitions(int n) {
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// todo
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return null;
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ArrayList<ArrayList<Integer>> answerList = intPartitionsHelper(n, n);
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int[][] answerArray = new int[answerList.size()][];
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for(int i = 0; i < answerList.size(); i++){
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answerArray[(answerList.size() - i) - 1] = new int[answerList.get(i).size()];
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for(int j = 0; j < answerList.get(i).size(); j++){
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answerArray[(answerList.size() - i) - 1][j] = answerList.get(i).get(j);
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}
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}
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return answerArray;
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}
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public static void main()
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public void main()
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{
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int n = 4;
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int[][] partitions = intPartitions(n);
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for (int i = 0; i < partitions.length; i++) {
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for(int j = 0; j < partitions[i].length; j++)
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System.out.print(partitions[i][j]);
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System.out.println();
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}
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}
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}
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