2 Commits
Author SHA1 Message Date
Ramtin 73056049fe implement intPartitions method in MainExercises 2026-04-21 15:40:44 +03:30
Ramtin cb480fe4e2 fix generateTriangle method logical bug 2026-04-21 14:40:14 +03:30
+59 -31
View File
@@ -1,11 +1,14 @@
import java.util.ArrayList;
public class MainExercises public class MainExercises
{ {
public char[][] generateTriangle(int n) { public char[][] generateTriangle(int n) {
char[][] result = new char[n][n]; char[][] result = new char[n][];
for (int i = 0; i < n; i++) for (int i = 0; i < n; i++)
{ {
result[i] = new char[i+1];
if (i == n-1) if (i == n-1)
{ {
for (int j = 0; j <= i; j++) for (int j = 0; j <= i; j++)
@@ -17,6 +20,8 @@ public class MainExercises
{ {
result[i][0] = '*'; result[i][0] = '*';
result[i][i] = '*'; result[i][i] = '*';
for (int j = 1; j < i; j++) result[i][j] = ' ';
} }
} }
@@ -58,37 +63,60 @@ public class MainExercises
return result; return result;
} }
/*
integer partitioning is a combinatorics problem in discreet maths
the problem is to generate sum numbers which their summation is the input number
e.g. 1 -> all partitions of integer 3 are:
3
2, 1
1, 1, 1
e.g. 2 -> for number 4 goes as:
4
3, 1
2, 2
2, 1, 1
1, 1, 1, 1
Note: As you can see in the examples, we want to generate distinct partitions,
which means 1,2 and 2,1 are not different — they count as the same combination.
You should generate all partitions of the input number.
Hint: You can determine the size and order of the arrays by finding the pattern
of partitions and their count. Trust me, this one's fun and easy :)
If you're familiar with Lists and ArrayLists, you can also edit the method's
body to use them instead of arrays.
*/
public int[][] intPartitions(int n) { public int[][] intPartitions(int n) {
// todo int[][] result;
return null; ArrayList<ArrayList<Integer>> mainArray = new ArrayList<>();
ArrayList<Integer> start = new ArrayList<>();
start.add(n);
mainArray.add(start);
while (true) {
ArrayList<Integer> latestArray = mainArray.get(mainArray.size() - 1);
Integer numberOfInterest = 0;
for (Integer number : latestArray)
{
if (number > 1) {
numberOfInterest = number;
break;
}
}
if (numberOfInterest == 0) break;
numberOfInterest--;
Integer remain = n - numberOfInterest;
ArrayList<Integer> newArray = new ArrayList<>();
newArray.add(numberOfInterest);
for (Integer number = numberOfInterest;;) {
if (number >= remain) {
newArray.add(remain);
break;
}
else {
newArray.add(number);
remain -= number;
}
}
mainArray.add(newArray);
}
result = new int[mainArray.size()][];
for (int i = 0; i < mainArray.size(); i++) {
ArrayList<Integer> array = mainArray.get(i);
result[i] = new int[array.size()];
for (int j = 0; j < array.size(); j++) {
result[i][j] = array.get(j);
}
}
return result;
} }