fix: improve comments

This commit is contained in:
2026-04-17 11:53:06 +03:30
parent 3ac2a41574
commit 5780e034f1
3 changed files with 62 additions and 32 deletions
+37 -16
View File
@@ -28,21 +28,38 @@ public class MainExercises
/*
given a matrix of random integers, you should do spiral traversal in it
e.g. if the matrix is as shown below:
1 2 3
4 5 6
7 8 9
then the spiral traversal of that is:
{1, 2, 3, 6, 9, 8, 7, 4, 5}
SPIRAL TRAVERSAL OF A RECTANGULAR MATRIX
so you should walk in that matrix in a curl and then add the numbers in order you've seen them in a 1D array
*/
public int[] spiralTraversal(int[][] values, int rows, int cols) {
Given a rectangular matrix (2D array) of integers, this method traverses
it in a spiral order (clockwise from outside to inside) and returns
the elements as a 1D array.
EXAMPLE:
Input matrix:
1 2 3
4 5 6
7 8 9
Spiral order: start at top-left (1), go right →, then down ↓,
then left ←, then up ↑, then repeat inward.
Result: {1, 2, 3, 6, 9, 8, 7, 4, 5}
so you should walk in that matrix in a curl and then add the numbers in order you've seen them in a 1D array
RECTANGULAR MATRIX ASSUMPTION:
This method assumes the input matrix is RECTANGULAR (all rows have
the same number of columns). In Java, we can verify this because
2D arrays might be jagged (rows of different lengths).
IMPORTANT: In Java, we do NOT need to pass rows and cols!
The 2D array 'matrix' knows its own dimensions:
- Number of rows: matrix.length
- Number of columns: matrix[0].length (if rectangular)
*/
public int[] spiralTraversal(int[][] matrix) {
// todo
return null;
}
/*
@@ -61,14 +78,18 @@ public class MainExercises
2, 1, 1
1, 1, 1, 1
note: as you can see in examples, we want to generate distinct summations, which means 1, 2 and 2, 1 are no different
you should generate all partitions of the input number and
Note: As you can see in the examples, we want to generate distinct partitions,
which means 1,2 and 2,1 are not different — they count as the same combination.
hint: you can measure the size and order of arrays by finding the pattern of partitions and their number
trust me, that one's fun and easy :)
You should generate all partitions of the input number.
if you're familiar with lists and arraylists, you can also edit method's body to use them instead of array
Hint: You can determine the size and order of the arrays by finding the pattern
of partitions and their count. Trust me, this one's fun and easy :)
If you're familiar with Lists and ArrayLists, you can also edit the method's
body to use them instead of arrays.
*/
public int[][] intPartitions(int n) {
// todo
return null;