feat: implement sorting algorithms in Python

This commit is contained in:
2026-04-12 03:00:46 +03:30
commit d0b7968cb2
5 changed files with 114 additions and 0 deletions
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# VS Code
.idea
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def bubble_sort(arr):
n = len(arr)
for i in range(n - 1):
swapped = False # To detect whether the move has been made at this stage or not
# Comparing adjacent elements
for j in range(n - i - 1): # -i because the largest elements are fixed at the end
if arr[j] > arr[j + 1]:
# Swap
arr[j], arr[j + 1] = arr[j + 1], arr[j]
swapped = True
# If no moves were made, the array was already sorted → Done!
if not swapped:
break
# Example:
nums = [5, 2, 4, 6, 1, 3]
print("Before sorting:", nums)
bubble_sort(nums)
print("After sorting:", nums)
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def insertion_sort(arr):
# starting from second index
for i in range (1, len(arr)):
key = arr[i] # The element we want to insert
j = i - 1 # Last house of sorted section
# Shift it right until the left member is greater than key
while j >= 0 and arr[j] > key:
arr[j+1] = arr[j]
j -= 1
# Finally, put the key in the right place
arr[j+1] = key
# Example:
nums = [5, 2, 4, 6, 1, 3]
print("Before sorting:", nums)
insertion_sort(nums)
print("After sorting:", nums)
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def merge_sort(arr):
# If the array length is less than 2, no sorting is needed
if len(arr) <= 1:
return arr
# Find the middle of the array
mid = len(arr) // 2
# Divide the array into two halves
left_half = merge_sort(arr[:mid])
right_half = merge_sort(arr[mid:])
# Merge two sorted halves
return merge(left_half, right_half)
def merge(left, right):
result = []
i = j = 0
# As long as there are elements left in both lists
while i < len(left) and j < len(right):
if left[i] <= right[j]:
result.append(left[i])
i += 1
else:
result.append(right[j])
j += 1
# Add the remaining elements (one of the lists may run out early)
result.extend(left[i:])
result.extend(right[j:])
return result
# Example:
nums = [5, 2, 4, 6, 1, 3]
print("Before sorting:", nums)
nums = merge_sort(nums)
print("After sorting:", nums)
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def selection_sort(arr):
n = len(arr)
for i in range(n - 1):
# Assume the current element is the smallest
min_index = i
# Checking the rest of the array to find the smallest one
for j in range(i + 1, n):
if arr[j] < arr[min_index]:
min_index = j # Update the index of the smallest number
# If the smallest number is not the first, replace
if min_index != i:
arr[i], arr[min_index] = arr[min_index], arr[i]
# Example:
nums = [5, 2, 4, 6, 1, 3]
print("Before sorting:", nums)
selection_sort(nums)
print("After sorting:", nums)